x^2(x+3)(x+4)=x+20

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Solution for x^2(x+3)(x+4)=x+20 equation:


Simplifying
x2(x + 3)(x + 4) = x + 20

Reorder the terms:
x2(3 + x)(x + 4) = x + 20

Reorder the terms:
x2(3 + x)(4 + x) = x + 20

Multiply (3 + x) * (4 + x)
x2(3(4 + x) + x(4 + x)) = x + 20
x2((4 * 3 + x * 3) + x(4 + x)) = x + 20
x2((12 + 3x) + x(4 + x)) = x + 20
x2(12 + 3x + (4 * x + x * x)) = x + 20
x2(12 + 3x + (4x + x2)) = x + 20

Combine like terms: 3x + 4x = 7x
x2(12 + 7x + x2) = x + 20
(12 * x2 + 7x * x2 + x2 * x2) = x + 20
(12x2 + 7x3 + x4) = x + 20

Reorder the terms:
12x2 + 7x3 + x4 = 20 + x

Solving
12x2 + 7x3 + x4 = 20 + x

Solving for variable 'x'.

Reorder the terms:
-20 + -1x + 12x2 + 7x3 + x4 = 20 + x + -20 + -1x

Reorder the terms:
-20 + -1x + 12x2 + 7x3 + x4 = 20 + -20 + x + -1x

Combine like terms: 20 + -20 = 0
-20 + -1x + 12x2 + 7x3 + x4 = 0 + x + -1x
-20 + -1x + 12x2 + 7x3 + x4 = x + -1x

Combine like terms: x + -1x = 0
-20 + -1x + 12x2 + 7x3 + x4 = 0

The solution to this equation could not be determined.

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